Welcome to your Trigonometry II(Senior Class Math Study by Topics) NAME EMAIL PHONE NUMBER 1. Find a positive angle between 0° and 360° that is equivalent to 650°44°124°290°23°2. In the diagram below , WXYZ is a cyclic quadrilateral in which WZ = 6cm, ZY = 8.5cm and the diagonal WY = 10 cm. Calculate <WXY21°115°76°95°3. Find the value of cos 200° sin 160° + sin (- 340°) cos (- 380°)-11204. Given that sin(A+B) = sinA cosB + cosA sinB, without using mathematical tables or calculator, evaluate sin 105°.√5/6 + √3/6√2/3√6/4+ √2/4√3/25. If sin 49° = 3/4, find the value of sin 581°.√7√2√3√7/46. Without using tables or any calculating device find the value ofsin35°cos5° - cos35°sin5°0-111/27. Find the values of cos (-11π/3)10-11/28. If sin A + cos A = 7/5 and sin A cos A =12/25, find the values of sin A and cos A3/5, 4/53/5, 1/32/3, 1/32/3, 4/59. Find the value ofsin 225°√2-1/√21/√2-√210. Solve the equation 4 cosx - 3 = 0 for 0° ≤x≤ 360°234°12.5°63°41.4°11. Find the value of tan 158°0.9362-0.7071-0.40401.373212. Find the values of csc (-1650°)201-113. Find the value of sec 210°√21/√2-1/√2-√214. Write the value of the angle in surd form tan 315°1/√3-1-√3√315. Simplify:cos acos a - 1cos2a1- cos a16. Find the angles between 0° and 360° whose sine is -0.9781235°23°443°258°17. If sinθ = -5/13, where θ is an angle between 270° and 360°, calculate , without using mathematical tables, the values of sin2θ169/120120/169-120/1692/518. Find the angles between 0° and 360° whose sine is 0.422625°113°324°422.3°19. PQRS is a quadrilateral with dimensions shown belowCalculate the length of the diagonal PR4 cm7 cm6cm10 cm20. Simplify: cosec xcot xsec xtan x21. Find the value of sin 405°0.84530.53210.70710.324522. Find the value of sin 145°0.23560.57360.34550.564323. If sec θ = 17/8 and θ is a positive acute angle, find the value of csc θ using Pythagoras theorem.csc θ = 17/15csc θ = 27/15csc θ = 17/19csc θ = 16/1524. Given that cosθ = 12/13, for 0°<θ<90° calculate without using tables or calculator1/2-57/65-6/734/3525. If θ is a positive acute angle and sec θ = 25/7, find the value of csc θ using trigonometric identity.csc θ = 25/24csc θ = 23/24csc θ = 1/4csc θ = 25/2726 out of 25