19/03/2020 Solving Algebraic Equations(Study by Topics Junior Class) 19/03/2020 0Comments by Gate Academy Welcome to your Solving Algebraic Equations(Study by Topics Junior Class) NAME EMAIL PHONE NUMBER If the equation px² - 6x + 1 = 0 has equal roots, the value of p is 6 4 9 3 The largest root of the equation (x - 1)² = 4x - 7 is 7 2 4 6 Solve the equation -48 + 11n - 20n + 12 = 0 0 -2 4 2 -4 One of the roots of the equation x² + kx - 15 = 0 is 3. The values of k and the other roots are, respectively -2, 5 2, -5 -5, -2 5, 2 If 5 is subtracted from twice a certain number, the result is the same as adding 8 to the original number. Express this statement as an equation. 2(5 - x) + 8 = x 2x + 5 = x -8 x - 25 = 8 + x 2x - 5 = x + 8 5 - 2x = x + 8 Solve the equation 5(x + 1) - 15 = 0 x = -6 x = 5 x = 2 x = -9 x = 3 One of the roots of the equation 6y² = 5 - 7y is -1/3 1/2 -1/2 5/3 The roots of the equation y + 2√y = 8 are 4, 2 16, 4 16, 1 4, 1 The positive root of a equation 4x² + 7x = 1, correct to e decimal places is 0.133 0.322 1.062 10.623 If y = 2/3 x + 1 and z = 2/3 y + 1, then the value of z when x = 66 is 61 31/2 21 31 Solve the equation 5x² = 3x 0 or 5 0 or 3 0 or 3/5 3 or 5 Solve the equation 6(y-4) + 3(y+7) = 6 0 2/3 1 3/2 Solve the equation 3x + 10 = x² 5 or -2 5 or 2 -5 or -2 -5 or 2 One of the roots of the equation x² + 9 = 0 is -9 3 none of these -3 Solve the equation 2x² - 3x - 27 = 0 3, 9/2 3/2, 9 -3, 9/2 -2/3, 9 When the number x is doubled and 7 is subtracted from it, the result is equal to 8. Represent the statement algebraically. 2x - 7 = 8 7 - 2x = 8 x/2 - 7 = 8 3(x - 7) = 8 2x = 7 - 8 Evaluate (xy² - yz²)(x²z - xyz) when x = 2, y = -2 and z = -½ -34 -30 0 -28 If P = R/ R+2 % R+2/ R, where R is a number which is neither 0 nor -2, then P = 1 P > 0 P ≤ 0 P ≥ 0 Solve for a in the equation 4 - 6a = -2 -1 1/3 1 3 -3 The equation whose roots are 1/2 and -7 is 2x² + 14x - 7 = 0 2x² - 13x - 7 = 0 2x² + 7x -14 = 0 2x² + 13x - 7 = 0 1 out of 20 Time is Up! Time's up