Operational Amplifier (Op-amp)
- The output is proportional to the difference between the two input voltages, given by:
- Vout = A0(V+ – V–)
- where V+ and V– are the voltages at the non-inverting and inverting terminals and A0 is the open-loop gain
- When the calculated output of an op-amp is greater than the supply voltage, the op-amp is said to be saturated and the output is equal to the supply voltage
- If the output is not saturated, the two inputs are virtually at the same voltage
- If V+ > V–, then the output is positive
- If V+ < V–, then the output is negative
Ideal Operational Amplifier Properties
- Infinite Input Impedance: No current enters or leaves either of the inputs
- Zero Output Impedance: The whole of the voltage voltage is provided across the output load
- Infinite Open-loop Gain: Even if there is only a slight difference between the input voltages, the op-amp will be saturated and the output will equal the supply voltage
- Infinite Bandwidth: All frequencies are amplified by the same factor
- Infinite Slew Rate: There is no delay between changes in the input and consequent changes in the output
- Zero Noise Contribution: An ideal op-amp does not produce any noise itself
Comparator
- An op-amp can be used to compare the two inputs and the output will switch from one saturation level to the other when one of the input voltages changes
- The inverting and non-inverting inputs are derived from two potential dividers, so only very small current flow.
- This examples shows a comparator being used to operate a small lamp when it gets dark
- In daylight, the LDR has low resistance (3 kΩ) and the non-inverting voltage is small, causing the op-amp to be negatively saturated (-9 V).
- Diode reverse-biased: lamp doesn’t light
- At A: 3/12 + 3 × 9 = 1.8 V
- At B: 15/15 + 15 × 9 = 4.5 V
- 1.8 – 4.5 = 2.7, therefore -ve saturation
- In darkness, the LDR has high resistance (18 kΩ) and the non-inverting voltage is high, causing the op-amp to be positively saturated
- Diode forward-biased: lamp lights
- At A: 18/12 + 18 × 9 = 5.4 V
- At B: 15/15 + 15 × 9 = 4.5 V
- 5.4 – 4.5 = 0.9, therefore +ve saturation
- The LDR could be replaced by other sensors.
Negative Feedback
- A fraction βof the output is fed back to the inverting input of the op-amp
- Though the negative feedback reduces the voltage gain of the amplifier, it will improve the accuracy and control
- Advantages of Negative Feedback:
- It increases the range of frequencies over which the voltage gain is constant (increased bandwidth)
- The amplifier is more stable
- There is less distortion
Inverting Amplifier
- The input voltage is applied to the inverting input through the input resistance R
- The non-inverting input is connected to zero-volt
- Negative feedback is applied to the inverting input through a resistor Rf
- The non-inverting input is at virtual earth:
- the op-amp hav a very large gain
- and the non-inverting input is earthed
- If the amplifier is not to saturate, inverting input must be (almost) at the earth potentials
- Since the input resistance of the op-amp is infinite, current in Rin = current in Rf
- Hence: p.d. across Rin/Rin = p.d. across Rf/Rf
- The potential at P is zero (virtual earth), so Vin – 0/Rin = 0 – Vout/Rf
- Therefore, the overall voltage gain is given by
- Voltage gain = Vout/Vin = Rf/Rin
Non-inverting Amplifier
- The input voltage is applied to the non-inverting input
- Negative feedback is provided by a potential divider consisting of resistors R1 and Rf
- As before, the current in the two resistors are equal and can written as
- Cross multiply and rearrange
- Therefore, the overall voltage gain is given by;
- Voltage gain = Vout/Vin = 1 + Rf/R1
Relays
- The output of op-amp cannot exceed 25 mA and 15 V so in order to operate electronic circuits which require large currents, a relay must be used at output of the op-amp
- A relay is an electromagnetic switch that can switch on or off a large current using a small current
- It consists of an electromagnet, which when energized by the small current, operates the contact, switching on or off the large current
- The diode D2 conducts only when the output of the op-amp is positive with respect to the earth
- A back e.m.f. is generated by the coil when the current in the relay is switched off, which may damage the op-amp
- The diode D1, connected across the coil, protects the op-amp from back e.m.f. by conducting this current
Light Emitting Diode (LED)
- A LED is a diode which emits light only when it is forward-biased, hence it can be used to indicate the state of the output of an op-amp
- The maximum allowed current through a forward-biased LED is 20 mA and has a breakdown voltage of about 5 V
- Hence, to protect a LED from large currents, a resistor is connected in series with it
- When the output is positive, the diode D1 is forward-biased and will conduct, emitting light
- When the output is negative, the diode D2 is reverse-biased and will conduct, emitting light
Calibration Curve
- To measure the output voltage of an op-amp, an analogue or digital voltmeter is required
- Using a calibration curve, we can match this output voltage to a physical quantity
- For example, to set the temperature for frost warning, a calibration curve between the temperature of the thermistor and the corresponding output voltage is created
- The output voltage corresponding to the frost warning temperature can be obtained from the calibration curve