Partial Fractions
- To split an improper fraction into partials, calculate the degree of the quotient and work out by comparing coefficients
- deg(Q(x)) = deg(N(x)) – deg(D(x))
- where:
- Q(x) is the quotient
- N(x) is the numerator
- D(x) is the denominator
Vertical Asymptote
- Making the denominator 0 resulting in ∞
- Example:
- y = 1/(x + 1)(x – 3)
- Thus vertical asymptotes at: x = -1 and 3
Horizontal Asymptote
- By dividing the top and bottom of a fraction by x, we can see what value y tends to when x becomes very large
- Example:
- y = 3x – 2/x + 1
- Divide the numerator and denominator by x
- y = 3x – 2/x ÷ x + 1/x = 3 – 2/x ÷ 1 + 1/x
- When x is very large, y = 3/1 = 3
- Thus the horizontal asymptote at: y = 3
Oblique Asymptotes
- These occur only with improper fraction
- Example:
- y = 2x – 1 + 2/x – 1 – 3/x + 2
- When x becomes very large, y ≈ 2x – 1
- Thus oblique asymptote at: y = 2x – 1
Sign Tables
- They are used to visualize graph as it shows which quadrant the graph lies
- Enter values of x which result in different parts of the fraction equaling zero
- Leave columns between each value of x and place signs to indicate whether the value is +ve or -ve in each cell
- Example
- y = 3x² + 3x + 6/(x + 3)(x – 2)

Curve Sketching
- When you sketch the curve, include the following;
- y-intercept
- x-intercepts
- Stationary points (maxima, minima, inflections)
- Vertical asymptote(s)
- Horizontal or oblique asymptote(s)
Examples
- The curve C has the equation y = x² – 4/x – 3
- Find the equations of the asymptotes
- From the first formula:
- deg(Q(x)) = deg(N(x)) – deg(D(x))
- Write the equation as partial fractions:
- y = x² – 4/x – 3 = Ax + B + C/x – 3
- (Ax + B)(x – 3) + C = x² – 4
- Ax² – 3Ax + Bx – 3B + C = x² – 4
- Finding the coefficients using algebraic manipulation:
- Ax² = x²
- ∴ A = 1
- -3Ax + Bx = 0x
- ∴ -3A + B = 0
- ∴ B = 3(1) = 3
- -3B + C = -4
- ∴ -3(3) + C = -4
- ∴ C = -4 + 9 = 5
- The final partial fraction can be expressed as:
- Vertical asymptote:
- Oblique asymptote:
- as x increases, y ≈ x + 3
- ∴ y = x + 3
- Draw a sketch of C and its asymptotes. Give the coordinates of the points of intersection of C with the coordinate axes
- We know the asymptotes but need the intercepts and stationary points
- y-intercept:
- x = 0
- ∴ y = 0 + 3 + 5/0 – 3 = 4/3
- ∴ coordinates = (0, 4/3)
- x-intercepts:
- y = 0
- ∴ x² – 4/x – 3 = 0
- x² – 4 = 0
- ∴ x = ±2
- Sketch
