Welcome to your Oscillations - Simple Harmonic Motion(Senior Class Physics Study by Topics) NAME EMAIL PHONE NUMBER 1. What happens to in a SHM system if you double the amplitude? It doublesIt halvesIt stays the sameIt is multiplied by 42. A particle undergoes simple harmonic motion with angular velocity of 3 rad/s and amplitude of 30 cm. It starts with maximum forward amplitude at time t = 0. Find the velocity at time t = 2 s. 0.114 m/s0.251 m/s3.21 m/s0.545 m/s3. In SHM restoring force is F = - kx, where k is force constant, x is displacement and a is amplitude of motion, then total energy depends upon K, a and mK, aK, x, mK, x4. A spring stretches 50 mm when a mass of 0.15 kg is hung from it (g = data sheet). The spring is extended a further 15 mm and released. Its Time Period and maximum acceleration are :- T = 2.8s; a = 76mm/s²T = 14.2s; a = 2.9mm/s²T = 14.2s; a = 76mm/s²T = 2.8s; a = 2.9mm/s²5. Below is the expression for: AccelerationNone of the aboveVelocityDisplacement6. What happens to time period of a SHM system if you double the amplitude?It stays the sameIt halvesIt is multiplied by 4It doubles since it has twice as far to go7. The above graph of a parabola can only be which of the following for a simple harmonic oscillator? Kinetic energy versus displacement graph.Kinetic energy versus time graphPotential energy versus displacement graphPotential energy versus time graph8. A mass m is vertically suspended from a spring of negligible mass, the system oscillates with a frequency n. What will be the frequency of the system, if a mass 4m is suspended from the same spring ?n/42nn/24n9. A body of mass m is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3 s. When the mass m is increased by 1 kg, the time period of oscillations becomes 5 s. The value of m in kg is4/39/1616/93/410. A simple harmonic oscillator has an amplitude a and time period T. The time required by it to travel from x = a to x = a/2 is T/4T/3T/2T/611. Which of the following is a simple harmonic motion?Particle moving in a circle with uniform speedBall bouncing between two vertical wallsWave moving through a string fixed at both endsEarth spinning about its axis12. A particle executing simple harmonic motion of amplitude 5cm has a maximum speed of 31.4 cm/s. The frequency of its oscillation is?3Hz4Hz2Hz1Hz13. The circular motion of a particle whose speed is constant is __________Simple harmonic but not periodicPeriod but not simple harmonicNeither periodic not simple harmoncPeriodic and Simple harmonic14. A fly of 2 g is flying at a speed of 5 m/s across the room. A spider of mass 100g is hanging underneath a line at rest. The fly flew by the spider and is eaten. Thus the spider starts to oscillate underneath the line. What is the maximum height they will reach? 0.0002 m0.0004 m0.0003 m0.0005 m15. A pendulum is set in motion from rest at t=0 with a displacement of 1.5cm and a time period of 2.0s.Which of the following is true about the motion:-It has a frequency of 0.5Hz and a maximum acceleration of 0.047m/s²It has a frequency of 2Hz and a maximum acceleration of 0.047m/s²It has a frequency of 0.5Hz and a maximum acceleration of 0.047m/s²It has a frequency of 0.5Hz and a maximum acceleration of 0.15m/s²16. A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration, then the time period is given by T=where g is equal to √g² + α²Gg - αg + α17. A linear harmonic oscillator of force constant 2 xN/m and amplitude 0.01 m has a total mechanical energy of 160 J. ItsMaximum potential energy is zeroMaximum potential energy is 160 JMinimum potential energy is 100 JMaximum potential energy is 100 J18. A mass oscillating on a spring completes 20 oscillations in 16s. If its amplitude is 2.2cm which of the following is true?Frequency 0.8Hz, maximum acceleration 0.11m/s²Frequency 1.25Hz, maximum acceleration 0.56m/s²Frequency 1.25Hz, maximum acceleration 1.4m/s²Frequency 1.25Hz, maximum acceleration 7.9m/s²19. An oscillating spring has its displacement x/mm described by the equationx = 4 cos ( 5t )After 0.5s its displacement and acceleration are:- X = -3.2mm; a = -80mm/s²X = 3.2mm; a = -80mm/s²X = -3.2mm; a = 80mm/s²X = 3.2mm; a = 80mm/s²20. What is the correct formula for the period of the simple harmonic motion of a mass, m, on a spring of constant, k?T = 2π√l/gT = 2π√m/kT = 1/2π√m/gT = 2π/A√k/m21. The composition of two simple harmonic motions of equal periods at right angle to each other and with a phase difference of n results in the displacement of the particle alongCircleStraight lineellipseFigure of eight22. A 2 kg mass is placed on the end of a spring with a constant 250 N/m. What will be the period of oscillation when the spring performs a simple harmonic motion? 0.56 s0.28 s70.2 s0.089 s23. In a simple harmonic motion, when the displacement is one-half the amplitude, what fraction of the total energy is kinetic? 1/21/43/4Zero24. There is a maximum amplitude during resonance of any system because:-The energy absorbed each oscillation = the energy lost each oscillationThe energy absorbed each oscillation depends on the damping of the systemThe natural frequency is just below the ideal driving frequencyThe energy lost each oscillation depends on the damping of the system25. What is the angular frequency of the oscillation? 3.3 rad/s4.4 rad/s2.2. rad/s1.1 rad/s26 out of 25Time is Up!