Welcome to your Oscillations - Simple Harmonic Motion(Senior Class Physics Study by Topics) NAME EMAIL PHONE NUMBER 1. A particle undergoes simple harmonic motion with an angular velocity of 5 rad/s and an amplitude of 50 cm. It starts with maximum forward amplitude at time t = 0. Find the displacement at time t = 10 s. 0.438 m 0.482 m 0.500 m 0.321 m 2. What is the correct formula for the period of the simple harmonic motion of a mass, m, on a spring of constant, k? T = 2π√l/g T = 2π/A√k/m T = 2π√m/k T = 1/2π√m/g 3. When an object is oscillating with SHM, its motion through the equilibrium position can best be described by:- Zero acceleration, maximum amplitude Zero amplitude, maximum acceleration Zero acceleration, maximum speed Zero displacement, maximum displacement 4. A pendulum of length 5.8m is displaced by 23cm and released (g = data sheet). The frequency and maximum speed of the subsequent motion are:- F = 0.12Hz; v = 30m/s F = 0.21Hz; v = 30m/s F = 0.21Hz; v = 0.30m/s F = 0.12Hz; v = 0.30m/s 5. Two simple pendulums of length 0.5 m and 2.0 m respectively are given small linear displacement in one direction at the same time. They will again be in the same phase when the pendulum of shorter length has completed oscillations 5 3 2 1 6. Which of the following is a simple harmonic motion? Ball bouncing between two vertical walls Particle moving in a circle with uniform speed Wave moving through a string fixed at both ends Earth spinning about its axis 7. The potential energy of a simple harmonic oscillator when the particle is half way to its end point is E/2 2 E/3 E/4 E/8 8. A long pendulum has a time period of 10 s. If the bob is displaced 2 m from the equilibrium position and released, how long will it take to move 1 m? 1.24 seconds 1.67 seconds 5.34 seconds 2.67 seconds 9. A particle undergoes simple harmonic motion with the angular velocity of 7 rad/s and amplitude of 2 m. It starts with maximum forward amplitude at time t = 0. Find the acceleration at time t = 6s. 9.81 m/s/s 1.23 m/s/s 39.2 m/s/s 82.4 m/s/s 10. The composition of two simple harmonic motions of equal periods at right angle to each other and with a phase difference of n results in the displacement of the particle along Straight line Figure of eight Circle ellipse 11. A linear harmonic oscillator of force constant 2 xN/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its Maximum potential energy is zero Maximum potential energy is 100 J Maximum potential energy is 160 J Minimum potential energy is 100 J 12. A body executes SHM with an amplitude a. At what displacement from the mean position, the potential energy of the body is one-fourth of its total energy ? Some other fraction A/2 A/4 3A/4 13. There is a maximum amplitude during resonance of any system because:- The energy absorbed each oscillation = the energy lost each oscillation The energy lost each oscillation depends on the damping of the system The natural frequency is just below the ideal driving frequency The energy absorbed each oscillation depends on the damping of the system 14. A pendulum is set in motion from rest at t=0 with a displacement of 1.5cm and a time period of 2.0s.Which of the following is true about the motion:- It has a frequency of 0.5Hz and a maximum acceleration of 0.15m/s² It has a frequency of 0.5Hz and a maximum acceleration of 0.047m/s² It has a frequency of 2Hz and a maximum acceleration of 0.047m/s² 15. The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are kgm/s kgs kgm/s² kg/s 16. The above graph of a parabola can only be which of the following for a simple harmonic oscillator? Kinetic energy versus time graph Potential energy versus displacement graph Potential energy versus time graph Kinetic energy versus displacement graph. 17. A mass m is vertically suspended from a spring of negligible mass, the system oscillates with a frequency n. What will be the frequency of the system, if a mass 4m is suspended from the same spring ? n/4 4n 2n n/2 18. A body is executing SHM. When the displacements from the mean position is 4 cm and 5 cm, the corresponding velocities of the body is 10 cm/s and 8 cm/s. Then, the time period of the body is 2π π π/2 3π/2 19. A spring stretches 50 mm when a mass of 0.15 kg is hung from it (g = data sheet). The spring is extended a further 15 mm and released. Its Time Period and maximum acceleration are :- T = 2.8s; a = 76mm/s² T = 14.2s; a = 76mm/s² T = 14.2s; a = 2.9mm/s² T = 2.8s; a = 2.9mm/s² 20. What is the angular frequency of the oscillation? 3.3 rad/s 4.4 rad/s 2.2. rad/s 1.1 rad/s 21. A body of mass m is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3 s. When the mass m is increased by 1 kg, the time period of oscillations becomes 5 s. The value of m in kg is 3/4 16/9 4/3 9/16 22. Which statement best describes simple harmonic motion? An oscillation that increase in amplitude over time. An oscillation that gets quicker and quicker. An oscillation with fixed period and amplitude which varies over time. An oscillation with a fixed period and fixed amplitude. 23. In SHM restoring force is F = - kx, where k is force constant, x is displacement and a is amplitude of motion, then total energy depends upon K, a K, a and m K, x K, x, m 24. What happens to in a SHM system if you double the amplitude? It halves It stays the same It doubles It is multiplied by 4 25. A 5 kg mass undergoes simple harmonic motion on spring with constant 70 N/m. If the amplitude of the oscillations are 3 m, what will the maximum speed be? 17.1 m/s 11.2 m/s 14.6 m/s 10.3 m/s 1 out of 25 Time is Up! Time's up
