Welcome to your Trigonometry(Senior Class Maths Study by Topics) NAME EMAIL PHONE NUMBER 1. If the radius of the earh is 6,370 km, the distance between two towns on latitudes 25°N and 20°S on the same meridian is (π = 22/7) 3,185 km 5,005 km 4,004 km 6,006 km 2. If there is no stop-over at Dubai, and the average speed of the airplane is 500km/hr, the total time taken for the plane to fly from Lagos to Kuala Lumpur via Dubai is approximately 10 h 7 h 5 h 8 h 3. Two locations on the parallel of latitude φ°S have a difference in longitude of θ°.If R = 6,370 km and π=22/7, the distance between the two locations in km, is approximately (111φ) cosθ° (111θ) cos φ° (56φ) cosθ° (222θ) cos φ° 4. Two towns are θ° apart on the same meridian. If the earth's radius is 6,370 km π = 22/7, their distance apart in km is approximately 167θ 111θ 222θ 56θ 5. A girl walks 30 m from a point P on a bearing of 040º to a point Q. She then walks 30 m on a bearing of 140º to a point R. How far is R from P 30 km 38.6 km 42.4 km 25.2 km 6. In a triangle PQR, <PQR = 60°, PQ = 3 cm and QR = 4 cm. Find |PR| 5 cm √13 cm 2√5 cm 2√3 cm 7. Three cities London, Seoul and Harare are such that Seoul is located 50 km away from London on a bearing of 065°. Harare is 100 km away from London on a bearing of 305°. The distance between Seoul and Harare is 50√7 km 50√2 km 50√5 km 50√3 km 8. Given that cos²θ - sin²θ = 1/8, find the value of tan θ √7/3 3√7 √7 3/√7 9. If the radius of the earth is 6,370 km, the distance between two towns on latitudes 25°N and 20°S on the same meridian is (π = 22/7) 4,004 km 5,005 km 6,006 km 3,185 km 10. From the top of a 100m high building, a man observes the top of a tree at an angle of depression of 30°. If the tree is 50 m tall, the angle of depression of the foot of the tree as viewed by the man is tan-1(2√3) tan-1(√3/2) tan-1(√3) tan-1(2√3/2) 11. The hypotenuse of a right-angled isosceles triangle is 8 units. The length of each of the other sides are 4(√2-1) 4√2 4 4/√2 12. A woman 1.65 m tall stood 50 m away from the foot of a tower and observed that the angle of elevation pf the top of the tower to be 50°. What is the height of the tower? 12 m 61.2 m 24.5 m 23m 13. Starting from town X(45°N, 17°E), an airplane flies to town Y(45°N, 47°E) along the parallel of latitude and later to a third town Z(60°N, 47°E) along the meridian.(R = 6,370 km, π= 22/7). The distance between X and Y along the parallel of latitude in km, is 5,005√2/ 3 5,005 5,005√3/ 2 5,005√2/ 3 14. The two perpendicular sides of a right-angled triangle are 9 cm and 12 cm in length. The smallest angle of the triangle is 30 degrees 36 degrees 53.1 degrees 36.9 degrees 15. The angle between latitudes 20°N and 74°N is 62° 54° 74° 94° 16. The bearing of N75°W can also be expressed as 285° 225° 165° 075° 17. The bearing of a point P from an observer Q is S37°W. The bearing of Q from P is S 53° W N 37° E S 37° E N 53° W 18. Starting from town X(45°N, 17°E), an airplane flies to town Y(45°N, 47°E) along the parallel of latitude and later to a third town Z(60°N, 47°E) along the meridian.(R = 6,370 km, π= 22/7). The distance between Y and Z along the meridian is 1,668 1/3 km 5,005 km 2,502 1/2 km 3,336 2/3 km 19. The value of 2cos 270° + sin 270° is 1 0 -1 -2 20. If m and n are the lengths of the diagonals of a rhombus of side x, andm² + n² = kx², the value of k is 4 3 2 1 21. From a point P 30 m away from the foot of a tree, the angle of elevation of the top of the tree is 30°. From a point Q on the opposite side of the tree, the angle of elevation of the top of the three is 45°. The distance between P and Q is 47.3 m 50 m 17.3 m 42 m 22. X and Y are two lakes on the earth's surface. X has a latitude 34°N and Y has latitude 15°S. If the lakes are on the same meridian ,calculate the distance between them along the meridian(Take 2πR = 40,000 km) 23km 5440km 540km 54km 23. A young man 1.7 m tall, while standing, measures the angle of elevation of the top of a pole as 40°. If he is 15 m from the pole, what is the height of the pole? 12.5 m 20.2 m 9 m 14.3 m 24. The difference in longitude betweenP(55°N, 12°W) and Q(15°S, 65°W) is 70° 53° 77° 40° 25. If sin θ = a/b, where θ is an acute angle,then cot θ equals √(b/ b²-a²) √(b+a)(b-a)/ a √(b²-a²)/ b a/ √(b²-a²) 1 out of 25 Time is Up! Time's up